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6n^2+7n-90=0
a = 6; b = 7; c = -90;
Δ = b2-4ac
Δ = 72-4·6·(-90)
Δ = 2209
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2209}=47$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-47}{2*6}=\frac{-54}{12} =-4+1/2 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+47}{2*6}=\frac{40}{12} =3+1/3 $
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